http://www.aaa3.net/sample-rating-scale-scores/
Statistics and .. discount (PLZ i really need a detailed solution)?
When offered a discount of 20 percent, a random sample 6 of customers in May the company reported an average of 4.17 on a "change-of-intent to buy the" scale and a standard deviation of 0.32. When offered a discount of 30 percent, a random sample of 7 clients an average of 4.00 and a standard deviation of 0.08 for its "change-of-intent buy "ratings. test the hypothesis that the 0.01 level in this company can store, there is a different population average in the intention of buying scale when a discount rate of 20% is offered and when the rate is 30%. What is the p-value test of equal population means? (Assume that a hypothesis two-sided alternative). Give an appropriate conclusion with respect to the study.Calculate confidence interval 90% of the population mean difference. PLZ PLZ I really some detail need a solution .. plz
Okay, so you're testing H_0: μ_1 ≠ μ_2 (null hypothesis: μ-sub-1 is not equal to μ-sub-2):. p_1 (20% discount) μ = 4.17 σ = 0.32 n P_2 = 6 (30% discount): μ = 4.00 σ = 0.08 n = 7 The level of significance: α = 0.01 What we to do is called a two-sample tests. Z would be too complicated for me to write the formula here, so I took a screenshot of my notes:. This is the formula for two-sample z test http://img390.imageshack.us/img390 / Connection 2615/testet4.jpg all the circumstances, we obtain: p = 0.2048780344 This means that we accept the null hypothesis that μ_1 ≠ μ_2 level. For the confidence interval, we know that a confidence interval for μ is C: http://img329.imageshack.us/img329/3997/testzn1.jpg Here is the upper z * (1 – C) / 2 critical value for the standard normal distribution normally found in a table). (The connection of these values Again, in a confidence interval 90%, we obtain: (-0.0506, 0.39056).
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